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#Slope and distance formula geometry pdf#
#Slope and distance formula geometry manual#

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#Slope and distance formula geometry manual#

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#Slope and distance formula geometry pdf#

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You now know the distance and the location of your enemy. Then make sure you find out the Square root to get it to a normal number again and there you go! Now that you have found Delta X and Delta Y (Change in X and change in Y) You can put it into the formula and launch your attack. You square it because that is required for the theorem to work. It starts out as D^2 = (x2 - x1)^2 this is basically taking the distance between the X value of where you are and the X value of where your enemy is. You can then use the distance formula which is just a variant of the Pythagorean theorem to calculate the distance. You must use the change in X and the change in Y on the coordinate plane.įirst, find out how many spaces over he is to the Left/Right of you (X Value) then you must see how many spaces Up/Down he is from you (Y value)

In order to calculate that distance you must use a coordinate graph to find that distance. This can be represented by the "Distance" (Hypotenuse). One thing that must be done before any action is made is finding the distance between you and the enemy. You have been tasked to intercept this force and destroy it. You have sighting reports and coordinates of an enemy fleet. Imagine this, you are the admiral of a ship in WW2. I really hope this helped you, I spent a long time explaining this lmao.įor those having trouble, it helped me to imagine a scenario that this could be used in.

Therefore, we replace the numbers so we get c (hypotenuse) = ( ( x1 - x2) ^2 + (y1 - y2) ^2). But what do 3 and 0 and 4 and 0 mean? The two x values and y values, respectively. We can expand this even further if we replace the 3 and 4 with how we got there, so c = sqrt( (3 - 0)^2 + (4 - 0)^2). Of course, we can square root both sides so we get c = sqrt( 3^2 + 4^2). The hypotenuse is the distance of the two points. We can now find the hypotenuse, if we replace a and b with the base height length, so we get 3^2 + 4^2 = c^2 (where c is the orange line, or hypotenuse). We found this, again, by subtracting the y values (4 - 0 = 0). The red line represents it, and it is a length of 4 units. How did we find this? We took one of the x values (3) and subtracted it by the other (0). This is the base, with a distance of 3 units. Look at the blue line going from (0,0) to (3,0). Now, imagine two points, let's say they are (0,0) and (3,4) to keep it simple. (intuitive solution, and how I learned this) only look at the graph, ignore everything on the sides and bottom. Here is the graph I am referring to in my explanation: I haven't read any of the article on this so I really hope I don't say the exact same thing he says.